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$x$	$f(x)$	$g(x)$
$1$	$-3$	$2$
$2$	$3$	$4$
$3$	$1$	$-4$
$4$	$-4$	$-1$
$5$	$2$	$5$

Use the table defining $f$ and $g$ to solve:
NOTE: Write Does not exist if the value does not exist.

a) $(f - g)(4) =$

b) $(f + g)(4) - (g-f)(5) =$

c) $\displaystyle \left(\frac{f}{g}\right)(4) =$

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