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The amount of force, $F\text{,}$ (in pounds) needed to loosen a rusty bolt with a wrench is inversely proportional to the length, $l\text{,}$ of the wrench. Thus,

$F = \frac{k}{l}$

If you increase the length of the wrench by 50% so that the new length is $1.5l\text{,}$ what happens to the amount of force required to loosen the bolt?

$F_\text{new}=\frac{1}{2}F_\text{old}$
$F_\text{new}=2F_\text{old}$
$F_\text{new}=\frac{3}{2}F_\text{old}$
$F_\text{new}=\frac{2}{3}F_\text{old}$

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