The form of the partial fraction decomposition of a rational function is given below.

$$\frac{-\left(4x^{2}+x+32\right)}{(x - 4)(x^2+9)} = \frac{A}{x - 4} + \frac{B x + C}{x^2+9}$$
$A =$ $B =$ $C =$

Now evaluate the indefinite integral.

$\displaystyle \int \frac{-\left(4x^{2}+x+32\right)}{(x - 4)(x^2+9)} dx =$