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Which of the following is a correct statement of the quadratic formula?

$x=-b \pm \dfrac{\sqrt{b^2-4ac}}{2a}$
$x=\dfrac{-b}{2a} \pm \dfrac{\sqrt{b^2-4ac}}{2a}$
$x=-b \pm \dfrac{b-\sqrt{4ac}}{2a}$
$x=-b \pm \dfrac{\sqrt{b^2-ac}}{a}$

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