A population of mosquitoes doubles every $10$ days. Time units in this problem are “day” singular. What is the daily percent growth of the population? A pattern of repeated doubling is the same thing as a pattern of repeated multiplication, in this case multiplication by $2\text{.}$ Therefore, the growth of the population is exponential. We need to translate the English sentence “A population of mosquitoes doubles every $10$ days” into a math sentence (a formula). We know there must be some initial population, call it $P$ and we know to multiply by $2$ every $10$ days. Therefore a formula could be $P(t)=$ (use a fractional exponent in your answer). The fractional exponent is then used to calculate the daily growth factor $2^{\frac{1}{10}} =$ (round to $3$ decimal places). From our growth factor we determine the daily percent growth as $(2^{\frac{1}{10}} -1) \cdot 100 =$ (Include units and round to $3$ decimal places)